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Mechanistically speaking, the acetal hydrolysis is a combination of all the same proton transfer, nucleophilic attack, and leaving group dissociation steps as in the acetal formation, but in reverse. So option 1 is correct. The acetal group protects aldehydes and ketones in basic conditions during, for example, lialh 4 or nabh 4 reduction or grignard reactions, after which it is removed by hydrolysis.

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When treated with aqueous acid, they can be hydrolyzed back to the starting aldehyde/ketone. Hydrolysis of a cyclic acetal results in the formation of a diol and either an aldehyde or a ketone, depending on the structure of the acetal Repeating a similar set of steps reveals the ketone and second hydroxyl.

The end product of the reaction yields the original ketone (or aldehyde) and the excess alcohol

Hydrolysis of cyclic acetals will yield aldehyde (ketone) and diols. First, an acid catalyst must be used because alcohol is a weak nucleophile The relative rate of hydrolysis of these compounds is rationalized by considering the influence of steric, inductive and stereoelectronic effects on t… Hydrolysis of a cyclic acetal will produce a diol and which other functional group

Here’s the best way to solve it When a cyclic acetal undergoes hydrolysis, it reacts with water to break the acetal linkage